HSC Commerce (Marketing and Salesmanship) 12th Board ExamMaharashtra State Board
Account
It's free!

User


Login
Create free account


      Forgot password?
Share
Notifications

View all notifications
Books Shortlist
Your shortlist is empty

Solution - Coefficient of rank correlation between x and y is 0.5 and ∑d2i= 42. Assuming that no ranks are repeated, find the number of pairs of observations. - HSC Commerce (Marketing and Salesmanship) 12th Board Exam - Mathematics and Statistics

Question

Coefficient of rank correlation between x and y is 0.5 and `sumd_i^2`= 42. Assuming that no ranks are repeated, find the number of pairs of observations.

Solution

`r=0.5`

`sumd_i^2=42`

`n=?`

`R=1-(6sumd_i^2)/(n(n^2-1))`

`0.5=1-(6(42))/(n(n^2-1))`

`=1-252/(n(n^2-1))`

`252/(n(n^2-1))=1-0.5`

`252/(n(n^2-1))=0.5`

`(n(n^2-1))=252/0.5xx10/10`

`=504`

put n=10

`10(99)=990`

put n=9

`9(80)=720`

put n=8

`8(63)=504`

`therefore n=8`

  Is there an error in this question or solution?

APPEARS IN

Video TutorialsVIEW ALL [1]

Solution for question: Coefficient of rank correlation between x and y is 0.5 and ∑d2i= 42. Assuming that no ranks are repeated, find the number of pairs of observations. concept: Rank Correlation. For the courses HSC Commerce (Marketing and Salesmanship), HSC Commerce
S