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Find the Probability Distribution of the Number of Successes in Two Tosses of a Die, Where a Success is Defined as - CBSE (Science) Class 12 - Mathematics

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Question

Find the probability distribution of the number of successes in two tosses of a die, where a success is defined as

(i) number greater than 4

(ii) six appears on at least one die

Solution

When a die is tossed two times, we obtain (6 × 6) = 36 number of observations.

Let X be the random variable, which represents the number of successes.

Here, success refers to the number greater than 4.

P (X = 0) = P (number less than or equal to 4 on both the tosses) = `4/6xx4/6 = 4/9`

P (X = 1) = P (number less than or equal to 4 on first toss and greater than 4 on second toss) + P (number greater than 4 on first toss and less than or equal to 4 on second toss)

`= 4/6xx2/6+4/6xx2/6=4/9`

P (X = 2) = P (number greater than 4 on both the tosses)

`= 2/6xx2/6= 1/9`

Thus, the probability distribution is as follows.

X 0 1 2
P(X) 4/9 4/9 1/9

(ii) Here, success means six appears on at least one die.

P (Y = 0 ) = P (six appears on  none of the dice) = 56 × 56 = 2536

P (Y = 1) = P (six appears on at least one of the dice) = 16 × 56 + 56 × 16 +16 × 16 =1136

Thus, the required probability distribution is as follows

Y 0 1
P(Y) 2536 1136
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Solution Find the Probability Distribution of the Number of Successes in Two Tosses of a Die, Where a Success is Defined as Concept: Random Variables and Its Probability Distributions.
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