#### Question

A random variable X has the following probability distribution:

then E(X)=....................

(a) 0.8

(b) 0.9

(c) 0.7

(d) 1.1

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#### Solution

**(a)**

X = x |
-2 |
-1 |
0 |
1 |
2 |
3 |

P(x) |
0.1 |
0.1 |
0.2 |
0.2 |
0.3 |
0.1 |

`E(X)=sumx_iP(x_i)`

=( -2) x 0.1 + ( -1) x 0.1+ 0 x 0.2 +1x 0.2+ 2 x 0.3 + 3 x 0.1

=0.2 - 0.1 + 0 + 0.2 + 0.6 + 0.3

=0.8

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#### Reference Material

Solution for question: A Random Variable X Has the Following Probability Distribution concept: null - Random Variables and Its Probability Distributions. For the courses HSC Science (Computer Science), HSC Science (General) , HSC Arts, HSC Science (Electronics), HSC Commerce, HSC Commerce (Marketing and Salesmanship)