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Sum
Radius of a circle with centre O is 25 cm. Find the distance of a chord from the centre if length of the chord is 48 cm.
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Solution
Perpendicular drawn from the centre of the circle to the chord bisects the chord.
So, PD = `1/2` CD = `48/2` = 24 cm
In Δ OPD,
We apply the pythagoras theorem,
OP² + PD² = OD²
⇒ OP² + 24² = 25²
⇒ OP² = 25² - 24² = 625 -576 = 49
⇒ OP² = 49
⇒ OP = 7 CM
Concept: Properties of Chord of a Circle
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