Question
Radius of a circle with centre O is 25 cm. Find the distance of a chord from the centre if length of the chord is 48 cm.
Solution
Perpendicular drawn from the centre of the circle to the chord bisects the chord.
So, PD = `1/2` CD = `48/2` = 24 cm
In Δ OPD,
We apply the pythagoras theorem,
OP² + PD² = OD²
⇒ OP² + 24² = 25²
⇒ OP² = 25² - 24² = 625 -576 = 49
⇒ OP² = 49
⇒ OP = 7 CM
Is there an error in this question or solution?
Solution Radius of a Circle with Centre O is 25 Cm. Find the Distance of a Chord from the Centre If Length of the Chord is 48 Cm. Concept: Properties of Chord of a Circle.
