###### Advertisements

###### Advertisements

Sum

Radius of a circle with centre O is 25 cm. Find the distance of a chord from the centre if length of the chord is 48 cm.

###### Advertisements

#### Solution

Perpendicular drawn from the centre of the circle to the chord bisects the chord.

So, PD = `1/2` CD = `48/2` = 24 cm

In Δ OPD,

We apply the pythagoras theorem,

OP² + PD² = OD²

⇒ OP² + 24² = 25²

⇒ OP² = 25² - 24² = 625 -576 = 49

⇒ OP² = 49

⇒ OP = 7 CM

Concept: Properties of Chord of a Circle

Is there an error in this question or solution?

#### APPEARS IN

#### RELATED QUESTIONS

In a circle with centre P, chord AB is drawn of length 13 cm, seg PQ ⊥ chord AB, then find l(QB).

O is centre of the circle. Find the length of radius, if the chord of length 24 cm is at a distance of 9 cm from the centre of the circle.

C is the centre of the circle whose radius is 10 cm. Find the distance of the chord from the centre if the length of the chord is 12 cm.