#### Question

Consider the D−T reaction (deuterium−tritium fusion)

`""_1^2H + ""_1^3H -> ""_2^4He + n`

Calculate the energy released in MeV in this reaction from the data:

`m(""_1^2H)`= 2.014102 u

`m(""_1^3H)`= 3.016049 u

#### Solution

Take the D-T nuclear reaction: `""_1^2H + ""_1^3H -> ""_2^4He + n`

It is given that:

Mass of `""_1^2H` *m*_{1}= 2.014102 u

Mass of `""_1^3H`* m*_{2 }= 3.016049 u

Mass of* `""_2^4He` m*_{3 }= 4.002603 u

Mass of `""_0^1n` *m*_{4 }= 1.008665 u

*Q*-value of the given D-T reaction is:

*Q* = [*m*_{1 }+ *m*_{2}− *m*_{3}* − m*_{4}] *c*^{2}

= [2.014102 + 3.016049 − 4.002603 − 1.008665] *c*^{2}

= [0.018883 *c*^{2}] u

But 1 u = 931.5 MeV/*c*^{2}

∴*Q* = 0.018883 × 931.5 = 17.59 MeV

Is there an error in this question or solution?

Solution Consider the D−T Reaction (Deuterium−Tritium Fusion) Calculate the Energy Released in Mev in this Reaction from the Data: Concept: Radioactivity - Beta Decay.