Department of Pre-University Education, KarnatakaPUC Karnataka Science Class 12
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A Point Source Emitting Alpha Particles is Placed at a Distance of 1 M from a Counter Which Records Any Alpha Particle Falling on Its 1 Cm2 Window. If the Source Contains - Physics

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Question

A point source emitting alpha particles is placed at a distance of 1 m from a counter which records any alpha particle falling on its 1 cm2 window. If the source contains 6.0 × 1016 active nuclei and the counter records a rate of 50000 counts/second, find the decay constant. Assume that the source emits alpha particles uniformly in all directions and the alpha particles fall nearly normally on the window.

Solution

Given:
Counts received per second = 50000 Counts/second
Number of active nuclei, N = 6 × 1016
Total counts radiated from the source, `"dN"/"dt"` = Total surface area × 50000 counts/cm2

= 4 × 3.14 × 1 × 104 × 5 × 104

= 6.28 × 109 Counts

We know

`"dN"/"dt" = lambdaN`

Here , `lambda` = Disintegration constant

`therefore lambda = (6.28 xx 10^9)/(6 xx 10^16)`

= `1.0467 xx 10^-7`

= `1.05 xx 10^-7  "s"^-1`

  Is there an error in this question or solution?

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Solution A Point Source Emitting Alpha Particles is Placed at a Distance of 1 M from a Counter Which Records Any Alpha Particle Falling on Its 1 Cm2 Window. If the Source Contains Concept: Radioactivity - Alpha Decay.
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