HSC Science (General) 12th Board ExamMaharashtra State Board
Account
It's free!

User


Login
Create free account


      Forgot password?
Share
Notifications

View all notifications
Books Shortlist
Your shortlist is empty

Solution - In Circular Motion, Assuming V = W * R , Obtain an Expression for the Resultant Acceleration of a Particle in Terms of Tangential and Radial Component. - HSC Science (General) 12th Board Exam - Physics

Question

In circular motion, assuming `bar v = bar w xx bar r` , obtain an expression for the resultant acceleration of a particle in terms of tangential and radial component.

Solution

Acceleration of a particle,

`a=lim_(deltat->0) ((delta v)/(delta t)) ... delta t ->0; delta t ne 0`

`therefore a=(dv)/(dt)`

`But, v = r omega`

`therefore a=d/dt (r omega)`

`=r (d omega)/dt + omega (dr)/(dt)`

`because "r is constant"`

`(dr)/(dt) = 0`

`therefore a=r (d omega)/(dt)`

`because (d omega)/(dt) = alpha`

`alpha = r alpha`

Given that:

`bar "v"= bar omega xx bar "r"`

Differentiating w.r.t. time

`(d bar v)/(dt)=d/dt (bar omega xx bar "r")`

`(d barv)/(dt) = (d baromega)/(dt) xx barr + baromega xx (d barr)/(dt)`

`(d barv)/(dt) = baralpha xx barr + baromega xx barv`

`therefore bara = bara_T + bara_r`

Where,

a = Linear acceleration

aT = Tangential component of linear acceleration

ar = Radial component of linear acceleration

Is there an error in this question or solution?

APPEARS IN

Video TutorialsVIEW ALL [1]

Solution for question: In Circular Motion, Assuming V = W * R , Obtain an Expression for the Resultant Acceleration of a Particle in Terms of Tangential and Radial Component. concept: null - Radial Acceleration. For the courses HSC Science (General) , HSC Science (Electronics), HSC Science (Computer Science)
S