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# Solution for An Organic Compound Contains 69% Carbon and 4.8% Hydrogen, the Remainder Being Oxygen. Calculate the Masses of Carbon Dioxide and Water Produced When 0.20 G of this Substance is Subjected to Complete Combustion. - CBSE (Science) Class 11 - Chemistry

ConceptQuantitative Analysis of Carbon and Hydrogen

#### Question

An organic compound contains 69% carbon and 4.8% hydrogen, the remainder being oxygen. Calculate the masses of carbon dioxide and water produced when 0.20 g of this substance is subjected to complete combustion.

#### Solution 1

Percentage of carbon in organic compound = 69 %

That is, 100 g of organic compound contains 69 g of carbon.

∴0.2 g of organic compound will contain = (69 xx 0.2)/100 = 0.138 g of C

Molecular mass of carbon dioxide, CO2 = 44 g

That is, 12 g of carbon is contained in 44 g of CO2.

Therefore, 0.138 g of carbon will be contained in  (44 xx 0.138)/12 = 0.506 g of CO2

Thus, 0.506 g of CO2 will be produced on complete combustion of 0.2 g of organic compound.

Percentage of hydrogen in organic compound is 4.8.

i.e., 100 g of organic compound contains 4.8 g of hydrogen.

Therefore, 0.2 g of organic compound will contain (4.8 xx 0.2)/100 = 0.0096 g of H

It is known that molecular mass of water (H2O) is 18 g.

Thus, 2 g of hydrogen is contained in 18 g of water.

∴0.0096 g of hydrogen will be contained in (18 xx 0.0096)/2 = 0.0864 g of water

Thus, 0.0864 g of water will be produced on complete combustion of 0.2 g of the organic compound.

#### Solution 2

Step I Calculation of Mass of CO_2 Produced

Mass of compound = 0.20 g

Percentage of carbon = 69 %

Percentage of carbon = 12/44 xx "Mass of carbon dioxide formed"/"Mass of compound" xx 100

69  = 12/44 xx "Mass of carbon dioxide formed"/(0.20 g)xx 100

:. Mass of CO_2 formed = (69 xx 44 xx (0.20g))/(12xx100) = 0.506 g

Step II Calulation of Mass of H_2O produced

Mass of Compound = 0.20 g

Percentage of Hydrogen  = 4.8 %

Percentage of hydorgen  =  2/18 xx "Mass of water formed"/"Mass of compoud" xx 100

4.8 xx 2/18 xx "Mass of water formed"/"(0.20 g)" xx 100

:. Mass of H_2O Formed = (4.8 xx 18 xx (0.20g))/(2xx100)` = 0.0864 g

Is there an error in this question or solution?

#### APPEARS IN

NCERT Solution for Chemistry Textbook for Class 11 (2016 to Current)
Chapter 12: Organic Chemistry - Some Basic Principles and Techniques
Q: 32 | Page no. 364
Solution An Organic Compound Contains 69% Carbon and 4.8% Hydrogen, the Remainder Being Oxygen. Calculate the Masses of Carbon Dioxide and Water Produced When 0.20 G of this Substance is Subjected to Complete Combustion. Concept: Quantitative Analysis of Carbon and Hydrogen.
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