Question
Solve `x = (3x + 1)/(4x)`
Solution
`x = (3x + 1)/(4x)`
`=> 4x^2 = 3x + 1`
`=> 4x^2 - 3x - 1 = 0`
`=> 4x^2 - 4x + x - 1 = 0`
`=> 4x(x - 1) + 1(x - 1) = 0`
=> (x - 1)(4x + 1) = 0
Since x - 1 = 0 or 4x + 1 = 0
then x = 1 or x = `(-1)/4`
Is there an error in this question or solution?
Solution Solve X = (3x + 1)/(4x) Concept: Quadratic Equations.
