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# In the Following, Find the Value Of K For Which the Given Value is a Solution of the Given Equation: X2 - X(A + B) + K = 0, X = a - Mathematics

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#### Question

In the following, find the value of k for which the given value is a solution of the given equation:

x2 - x(a + b) + k = 0, x = a

#### Solution 1

We are given here that,

x2 - x(a + b) + k = 0, x = a

Now, as we know that x = a is a solution of the quadratic equation, hence it should satisfy the equation. Therefore substituting x = a in the above equation gives us,

x2 - x(a + b) + k = 0

a2 - a(a + b) + k = 0

a2 - a2 - ab + k = 0

k = ab

Hence, the value of k = ab.

#### Solution 2

We are given here that,

x2 - x(a + b) + k = 0, x = a

Now, as we know that x = a is a solution of the quadratic equation, hence it should satisfy the equation. Therefore substituting x = a in the above equation gives us,

x2 - x(a + b) + k = 0

a2 - a(a + b) + k = 0

a2 - a2 - ab + k = 0

k = ab

Hence, the value of k = ab.

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#### APPEARS IN

RD Sharma Solution for Class 10 Maths (2018 (Latest))