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In the Following, Find the Value Of K For Which the Given Value is a Solution of the Given Equation: X2 - X(A + B) + K = 0, X = a - CBSE Class 10 - Mathematics

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Question

In the following, find the value of k for which the given value is a solution of the given equation:

x2 - x(a + b) + k = 0, x = a

Solution 1

We are given here that,

x2 - x(a + b) + k = 0, x = a

Now, as we know that x = a is a solution of the quadratic equation, hence it should satisfy the equation. Therefore substituting x = a in the above equation gives us,

x2 - x(a + b) + k = 0

a2 - a(a + b) + k = 0

a2 - a2 - ab + k = 0

k = ab

Hence, the value of k = ab.

Solution 2

We are given here that,

x2 - x(a + b) + k = 0, x = a

Now, as we know that x = a is a solution of the quadratic equation, hence it should satisfy the equation. Therefore substituting x = a in the above equation gives us,

x2 - x(a + b) + k = 0

a2 - a(a + b) + k = 0

a2 - a2 - ab + k = 0

k = ab

Hence, the value of k = ab.

  Is there an error in this question or solution?

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Solution In the Following, Find the Value Of K For Which the Given Value is a Solution of the Given Equation: X2 - X(A + B) + K = 0, X = a Concept: Quadratic Equations.
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