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In the Following, Find the Value Of K For Which the Given Value is a Solution of the Given Equation: X2 + 3ax + K = 0, X = -a - CBSE Class 10 - Mathematics

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Question

In the following, find the value of k for which the given value is a solution of the given equation:

x2 + 3ax + k = 0, x = -a

Solution

We are given here that,

x2 + 3ax + k = 0, x = -a

Now, as we know that x = -a is a solution of the quadratic equation, hence it should satisfy the equation. Therefore substituting x = -a in the above equation gives us,

x2 + 3ax + k = 0

(-a)2 + 3a(-a) + k =0

a2 - 3a2 + k = 0

-2a2 + k = 0

k = 2a2

Hence the value of k = 2a2.

  Is there an error in this question or solution?

APPEARS IN

Solution In the Following, Find the Value Of K For Which the Given Value is a Solution of the Given Equation: X2 + 3ax + K = 0, X = -a Concept: Quadratic Equations.
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