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# In the Following, Find the Value of K for Which the Given Value is a Solution of the Given Equation: Kx^2+Sqrt2x-4=0, X=Sqrt2 - Mathematics

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#### Question

In the following, find the value of k for which the given value is a solution of the given equation:

kx^2+sqrt2x-4=0, x=sqrt2

#### Solution

We are given here that,

kx^2+sqrt2x-4=0, x=sqrt2

Now, as we know that x=sqrt2 is a solution of the quadratic equation, hence it should satisfy the equation. Therefore substituting x=sqrt2 in the above equation gives us,

kx^2+sqrt2x-4=0

k(sqrt2)^2+sqrt2(sqrt2)-4=0

2k + 2 - 4 = 0

2k - 2 = 0

2k = 2

k=2/2

k = 1

Hence, the value of k = 1.

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#### APPEARS IN

RD Sharma Solution for Class 10 Maths (2018 (Latest))
In the Following, Find the Value of K for Which the Given Value is a Solution of the Given Equation: Kx^2+Sqrt2x-4=0, X=Sqrt2 Concept: Quadratic Equations.