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In the Following, Find the Value Of K For Which the Given Value is a Solution of the Given Equation: 7x2 + Kx - 3 = 0, `X=2/3` - CBSE Class 10 - Mathematics

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Question

In the following, find the value of k for which the given value is a solution of the given equation:

7x2 + kx - 3 = 0, `x=2/3`

Solution

e are given here that,

7x2 + kx - 3 = 0, `x=2/3`

Now, as we know that `x=2/3` is a solution of the quadratic equation, hence it should satisfy the equation. Therefore substituting `x=2/3` in the above equation gives us,

7x2 + kx - 3 = 0

`7(2/3)^2+k(2/3)-3=0`

`7(4/9)+(2k)/3-3=0`

`28/9+(2k/3)-3=0`

`(2k)/3=3-28/9`

`(2k)/3=(27-28)/9`

`(2k)/3=(-1)/9`

`2k=(-1)/9xx3`

`2k=(-3)/9`

`k=((-3)/9)/2`

`k=(-3)/(9xx2)`

`k=(-3)/18`

`k=(-1)/6`

Hence, the value of `k=(-1)/6`

  Is there an error in this question or solution?

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Solution In the Following, Find the Value Of K For Which the Given Value is a Solution of the Given Equation: 7x2 + Kx - 3 = 0, `X=2/3` Concept: Quadratic Equations.
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