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In the Following, Determine Whether the Given Values Are Solutions of the Given Equation Or Not: X2 + X + 1 = 0, X = 0, X = 1 - Mathematics

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Question

In the following, determine whether the given values are solutions of the given equation or not:

2x2 - x + 9 = x2 + 4x + 3, x = 2, x =3

Solution

We have been given that,

2x2 - x + 9 = x2 + 4x + 3

2x2 - x + 9 - x2 - 4x - 3 = 0

x2 - 5x + 6 = 0, x = 2, x = 3

Now if x = 2 is a solution of the equation then it should satisfy the equation.

So, substituting x = 2 in the equation, we get

x2 - 5x + 6

= (2)2 - 5(2) + 6

= 4 - 10 + 6

= 0

Hence x = 2 is a solution of the given quadratic equation

Also, if x = 3 is a solution of the equation then it should satisfy the equation.

So, substituting x = 3 in the equation, we get

x2 - 5x + 6

= (3)2 - 5(3) + 6

= 9 - 15 + 6

= 0

Hence x = 3 is a solution of the quadratic equation.

Therefore, from the above results we find out that both x = 2 and x = 3 are solutions of the quadratic equation.

  Is there an error in this question or solution?
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APPEARS IN

 RD Sharma Solution for Class 10 Maths (2018 (Latest))
Chapter 4: Quadratic Equations
Ex. 4.1 | Q: 2.5 | Page no. 4
 RD Sharma Solution for Class 10 Maths (2018 (Latest))
Chapter 4: Quadratic Equations
Ex. 4.1 | Q: 2.5 | Page no. 4
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In the Following, Determine Whether the Given Values Are Solutions of the Given Equation Or Not: X2 + X + 1 = 0, X = 0, X = 1 Concept: Quadratic Equations.
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