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# In the Following, Determine Whether the Given Values Are Solutions of the Given Equation Or Not: X^2-sqrt2x-4=0, X=-sqrt2, X=-2sqrt2 - Mathematics

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#### Question

In the following, determine whether the given values are solutions of the given equation or not:

x^2-sqrt2x-4=0, x=-sqrt2, x=-2sqrt2

#### Solution

We have been given that,

x^2-sqrt2x-4=0, x=-sqrt2, x=-2sqrt2

Now if x=-sqrt2 is a solution of the equation then it should satisfy the equation.

So, substituting x=-sqrt2 in the equation, we get

x^2-sqrt2x-4

=(-sqrt2)^2-sqrt2(-sqrt2)-4

= 2 + 2 - 4

= 0

Hence x=-sqrt2 is a solution of the quadratic equation.

Also, if x=-2sqrt2 is a solution of the equation then it should satisfy the equation.

So, substituting x=-2sqrt2 in the equation, we get

x^2-sqrt2x-4

(-2sqrt2)^2-sqrt2(-2sqrt2)-4

= 8 + 4 - 4

= 8

Hence x=-2sqrt2is not a solution of the quadratic equation.

Therefore, from the above results we find out that x=-sqrt2 is a solution but x=-2sqrt2is not a solution of the given quadratic equation.

Is there an error in this question or solution?

#### APPEARS IN

RD Sharma Solution for Class 10 Maths (2018 (Latest))
In the Following, Determine Whether the Given Values Are Solutions of the Given Equation Or Not: X^2-sqrt2x-4=0, X=-sqrt2, X=-2sqrt2 Concept: Quadratic Equations.