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In the Following, Determine Whether the Given Values Are Solutions of the Given Equation Or Not: `X^2 - 3sqrt3x+6=0`, `X=Sqrt3`, `X=-2sqrt3` - Mathematics

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Question

In the following, determine whether the given values are solutions of the given equation or not:

`x^2 - 3sqrt3x+6=0`, `x=sqrt3`, `x=-2sqrt3`

Solution

We have been given that,

`x^2 - 3sqrt3x+6=0`, `x=sqrt3`, `x=-2sqrt3`

Now if `x=sqrt3` is a solution of the equation then it should satisfy the equation.

So, substituting `x=sqrt3` in the equation, we get

`x^2 - 3sqrt3x+6`

`=(sqrt3)^2-3sqrt3(sqrt3)+6`

= 3 - 9 + 6

= 0

Hence `x=sqrt3` is a solution of the quadratic equation.

Also, if `x=-2sqrt3` is a solution of the equation then it should satisfy the equation

So, substituting `x=-2sqrt3` in the equation, we get

`x^2 - 3sqrt3x+6`

`=(-2sqrt3)^2-3sqrt3(-2sqrt3)+6`

= 12 - 18 + 6

= 0

Hence `x=-2sqrt3` is a solution of the quadratic equation.

Therefore, from the above results we find out that `x=sqrt3` and `x=-2sqrt3` are the solutions of the given quadratic equation.

  Is there an error in this question or solution?
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APPEARS IN

 RD Sharma Solution for Class 10 Maths (2018 (Latest))
Chapter 4: Quadratic Equations
Ex. 4.1 | Q: 2.3 | Page no. 4
 RD Sharma Solution for Class 10 Maths (2018 (Latest))
Chapter 4: Quadratic Equations
Ex. 4.1 | Q: 2.3 | Page no. 4
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Solution In the Following, Determine Whether the Given Values Are Solutions of the Given Equation Or Not: `X^2 - 3sqrt3x+6=0`, `X=Sqrt3`, `X=-2sqrt3` Concept: Quadratic Equations.
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