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In the Following, Determine Whether the Given Values Are Solutions of the Given Equation Or Not: `X^2 - 3sqrt3x+6=0`, `X=Sqrt3`, `X=-2sqrt3` - CBSE Class 10 - Mathematics

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Question

In the following, determine whether the given values are solutions of the given equation or not:

`x^2 - 3sqrt3x+6=0`, `x=sqrt3`, `x=-2sqrt3`

Solution

We have been given that,

`x^2 - 3sqrt3x+6=0`, `x=sqrt3`, `x=-2sqrt3`

Now if `x=sqrt3` is a solution of the equation then it should satisfy the equation.

So, substituting `x=sqrt3` in the equation, we get

`x^2 - 3sqrt3x+6`

`=(sqrt3)^2-3sqrt3(sqrt3)+6`

= 3 - 9 + 6

= 0

Hence `x=sqrt3` is a solution of the quadratic equation.

Also, if `x=-2sqrt3` is a solution of the equation then it should satisfy the equation

So, substituting `x=-2sqrt3` in the equation, we get

`x^2 - 3sqrt3x+6`

`=(-2sqrt3)^2-3sqrt3(-2sqrt3)+6`

= 12 - 18 + 6

= 0

Hence `x=-2sqrt3` is a solution of the quadratic equation.

Therefore, from the above results we find out that `x=sqrt3` and `x=-2sqrt3` are the solutions of the given quadratic equation.

  Is there an error in this question or solution?

APPEARS IN

Solution In the Following, Determine Whether the Given Values Are Solutions of the Given Equation Or Not: `X^2 - 3sqrt3x+6=0`, `X=Sqrt3`, `X=-2sqrt3` Concept: Quadratic Equations.
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