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# In the Following, Determine Whether the Given Values Are Solutions of the Given Equation Or Not: X^2 - 3sqrt3x+6=0, X=Sqrt3, X=-2sqrt3 - Mathematics

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#### Question

In the following, determine whether the given values are solutions of the given equation or not:

x^2 - 3sqrt3x+6=0, x=sqrt3, x=-2sqrt3

#### Solution

We have been given that,

x^2 - 3sqrt3x+6=0, x=sqrt3, x=-2sqrt3

Now if x=sqrt3 is a solution of the equation then it should satisfy the equation.

So, substituting x=sqrt3 in the equation, we get

x^2 - 3sqrt3x+6

=(sqrt3)^2-3sqrt3(sqrt3)+6

= 3 - 9 + 6

= 0

Hence x=sqrt3 is a solution of the quadratic equation.

Also, if x=-2sqrt3 is a solution of the equation then it should satisfy the equation

So, substituting x=-2sqrt3 in the equation, we get

x^2 - 3sqrt3x+6

=(-2sqrt3)^2-3sqrt3(-2sqrt3)+6

= 12 - 18 + 6

= 0

Hence x=-2sqrt3 is a solution of the quadratic equation.

Therefore, from the above results we find out that x=sqrt3 and x=-2sqrt3 are the solutions of the given quadratic equation.

Is there an error in this question or solution?
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#### APPEARS IN

RD Sharma Solution for Class 10 Maths (2018 (Latest))
Chapter 4: Quadratic Equations
Ex. 4.1 | Q: 2.3 | Page no. 4
RD Sharma Solution for Class 10 Maths (2018 (Latest))
Chapter 4: Quadratic Equations
Ex. 4.1 | Q: 2.3 | Page no. 4
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#### Video TutorialsVIEW ALL [5]

Solution In the Following, Determine Whether the Given Values Are Solutions of the Given Equation Or Not: X^2 - 3sqrt3x+6=0, X=Sqrt3, X=-2sqrt3 Concept: Quadratic Equations.
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