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In a Certain Positive Fraction, the Denominator is Greater than the Numerator by 3. If 1 is Subtracted from the Numerator and the Denominator Both, the Fraction Reduces By. Find the Fraction. - ICSE Class 10 - Mathematics

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Question

In a certain positive fraction, the denominator is greater than the numerator by 3. If 1 is subtracted from the numerator and the denominator both, the fraction reduces by. Find the fraction.

Solution

Let the fraction be `x/(x + 3)`

When 1 is subtracted from both numerator and denominator, then the fraction be comes `(x - 1)/(x + 2)`

From the given information we have

`x/(x + 3) - 1/14 = (x - 1)/(x + 2) `

`(14x - x - 3)/(14(x + 3)) = (x - 1)/(x + 2)`

`(13x +- 3)/(14(x + 3)) = (x - 1)/(x + 2)`

`(13x - 3)(x + 2) = 14(x^2 + 28x - 42)`

`x^2 + 5x - 36 = 0` 

`x^2 + 9x - 4x - 36 = 0`

x(x + 9)(x - 4) = 0

(x + 9)(x - 4) = 0

x = -9, 4

Since x cannot be negative So x = 4

Hence the fraction is `x/(x + 3) = 4/7`

  Is there an error in this question or solution?

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 Selina Solution for Selina ICSE Concise Mathematics for Class 10 (2018-2019) (2017 to Current)
Chapter 6: Solving (simple) Problems (Based on Quadratic Equations)
Ex.6E | Q: 13
Solution In a Certain Positive Fraction, the Denominator is Greater than the Numerator by 3. If 1 is Subtracted from the Numerator and the Denominator Both, the Fraction Reduces By. Find the Fraction. Concept: Quadratic Equations.
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