ICSE Class 10CISCE
Share
Notifications

View all notifications
Books Shortlist
Your shortlist is empty

Find the Two Natural Numbers Which Differ by 5 and the Sum of Whose Squares is 97. - ICSE Class 10 - Mathematics

Login
Create free account


      Forgot password?

Question

Find the two natural numbers which differ by 5 and the sum of whose squares is 97.

Solution

Let the two numbers be x and x + 5.
From the given information,
x2 + (x + 5)2 = 97
2x2 + 10x + 25 – 97 = 0
2x2 + 10x – 72 = 0
x2 + 5x – 36 = 0
(x + 9) (x – 4) = 0
x = -9 or 4
Since, -9 is not a natural number. So, x = 4.
Thus, the numbers are 4 and 9.

  Is there an error in this question or solution?

APPEARS IN

 Selina Solution for Selina ICSE Concise Mathematics for Class 10 (2018-2019) (2017 to Current)
Chapter 6: Solving (simple) Problems (Based on Quadratic Equations)
Ex.6A | Q: 3
Solution Find the Two Natural Numbers Which Differ by 5 and the Sum of Whose Squares is 97. Concept: Quadratic Equations.
S
View in app×