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# Divide 15 into Two Parts Such that the Sum of Their Reciprocals is 3/10 - Mathematics

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#### Question

Divide 15 into two parts such that the sum of their reciprocals is 3/10

#### Solution

Let the two parts be x and x - 15.

1/x + 1/(15 - x) = 3/10

(15 - x + x)/(x(15 - x)) = 3/10

15/(15x - x^2) = 3/10

150 = 45x - 3x^2

3x^2 - 45x - 3x^2

x^2 - 15x + 50 = 0

(x - 5)(x - 10) = 0

x = 5, 10

x = 5 => One part = 5 and other parts = 10

x = 10 => One parts = 10 and other part = 5

Thus the required two parts are 5 and 10.

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