#### Question

A trader buys x articles for a total cost of Rs 600.

(i) Write down the cost of one article in terms of x.

If the cost per article were Rs 5 more, the number of articles that can be bought for Rs 600 would be four less.

(ii) Write down the equation in x for the above situation and solve it for x.

#### Solution

Number of articles = x

The total cost of articles = Rs 600

1) Cost of one article = Rs `600/"x"`

2) From the given information we have

`600/(x - 4) - 600/x = 5`

`(600x - 600 x + 2400)/(x(x - 4)) = 5`

`480/(x(x - 4)) = 1`

`x^2 - 4x - 480 = 0`

`x^2 - 24x + 20x - 480 = 0`

x(x - 24) + 20(x - 24) = 0

(x - 24)(x + 20) = 0

x = 24, -20

Since number of article cannnot be negative So x = 24.

Is there an error in this question or solution?

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Solution A Trader Buys X Articles for a Total Cost of Rs 600. (I) Write Down the Cost of One Article in Terms of X. If the Cost per Article Were Rs 5 More, the Number of Articles that Can Be Bought Concept: Quadratic Equations.

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