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# A Cottage Industry Produces a Certain Number of Toys in a Day. the Cost of Production of Each Toy (In Rupees) Was Found to Be 55 Minus the Number of Articles Produced in a Day. on a Particular Day, the Total Cost of Production Was Rs. 750. If X Denotes the Number of Toys Produced that Day, Form the Quadratic Equation Fo Find X. - Mathematics

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#### Question

A cottage industry produces a certain number of toys in a day. The cost of production of each toy (in rupees) was found to be 55 minus the number of articles produced in a day. On a particular day, the total cost of production was Rs. 750. If x denotes the number of toys produced that day, form the quadratic equation fo find x.

#### Solution

Given that x denotes the no of toys product in a day

⇒ The cost of production of each by = 55 - no. of toys produced in a day

⇒ (55 - x)

Total cost of production is nothing but product of no. of toys produced in a day and cost of

production of each toy

⇒ x(55 - x)

But total cost of production = Rs 750

⇒ x(55 - x) = 750

⇒ 55x - x2 = 750

⇒ 55x - x2 - 750 = 0

⇒ -(55x - x2 - 750) = 0

⇒ x2 -55x + 750 = 0

∴ The required quadratic from of the given data is

x2 -55x + 750 = 0

Is there an error in this question or solution?

#### APPEARS IN

RD Sharma Solution for Class 10 Maths (2018 (Latest))