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# A Car Made a Run of 390 Km in ‘X’ Hours. If the Speed Had Been 4 Km/Hour More, It Would Have Taken 2 Hours Less for the Journey. Find ‘X’. - Mathematics

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#### Question

A car made a run of 390 km in ‘x’ hours. If the speed had been 4 km/hour more, it would have taken 2 hours less for the journey. Find ‘x’.

#### Solution

Let the original speed of the car be y km/hr

We know

Speed = "Distance"/"Time"

:. y = 390/x

=> x = 390/y ....(1)

New speed of the car = (y + 4) km/hr

New time taken by the car to cover 390 km = 390/(y + 4)

From the given information

390/y - 390/(y + 4) = 2

(390y = 1560 - 390y)/(y(y + 4) = 2)

780/(y^2 + 4y) = 1

y^2 + 4y - 780 = 0

y^2 + 4y - 780 = 0

y^2 + 30y - 26y - 780 = 0

y(y + 30) - 26(y + 30) = 0

(y + 30)(y - 26) = 0

y = -30,26

Since time cannot be negative so y = 26 From 1 we have

x = 390/y = 390/26 = 15

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#### APPEARS IN

Selina Solution for Concise Mathematics for Class 10 ICSE (2020 (Latest))
Chapter 6: Solving (simple) Problems (Based on Quadratic Equations)
Exercise 6(C) | Q: 6 | Page no. 73
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#### Video TutorialsVIEW ALL [5]

A Car Made a Run of 390 Km in ‘X’ Hours. If the Speed Had Been 4 Km/Hour More, It Would Have Taken 2 Hours Less for the Journey. Find ‘X’. Concept: Quadratic Equations.
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