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Q.19 - Mathematics

Sum

Q.19

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Solution

Let a annd a' be the first terms and d be the common difference of two A.P.s

Given, 

`t_50-t'_50=50`

`⇒ (a+49d)-(a'-49d)=50`

`⇒ a-a'=50`

Now, 

`t_80-t'80=(a+79d)-(a'-79d)`

            `   =a-a'`

            `=50`

Concept: Arithmetic Progression - Finding Sum of Their First ‘N’ Terms.
  Is there an error in this question or solution?
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