# Solution - Pythagoras Theorem

Account
Register

Share

Books Shortlist
Your shortlist is empty
ConceptPythagoras Theorem

#### Question

In a right triangle ABC right-angled at C, P and Q are the points on the sides CA and CB respectively, which divide these sides in the ratio 2 : 1. Prove that

(i) 9 AQ^2 = 9 AC^2 + 4 BC^2

(ii) 9 BP^2 = 9 BC^2 + 4 AC^2

(iii) 9 (AQ^2 + BP^2 ) = 13 AB^2

#### Solution

You need to to view the solution
Is there an error in this question or solution?

#### Similar questions VIEW ALL

In figure, ∠B of ∆ABC is an acute angle and AD ⊥ BC, prove that AC2 = AB2 + BC2 – 2BC × BD

view solution

A guy wire attached to a vertical pole of height 18 m is 24 m long and has a stake attached to the other end. How far from the base of the pole should the stake be driven so that the wire will be taut?

view solution

P and Q are the mid-points of the sides CA and CB respectively of a ∆ABC, right angled at C. Prove that:

(i) 4AQ^2 = 4AC^2 + BC^2

(ii) 4BP^2 = 4BC^2 + AC^2

(iii) (4AQ^2 + BP^2 ) = 5AB^2

view solution

In a right triangle ABC, right-angled at B, BC = 12 cm and AB = 5 cm. The radius of the circle inscribed in the triangle (in cm) is
(A) 4
(B) 3
(C) 2
(D) 1

view solution

PQR is a triangle right angled at P and M is a point on QR such that PM ⊥ QR. Show that PM2 = QM . MR

view solution

#### Reference Material

Solution for concept: Pythagoras Theorem. For the course 8th-10th CBSE
S