#### Question

In a right triangle ABC right-angled at C, P and Q are the points on the sides CA and CB respectively, which divide these sides in the ratio 2 : 1. Prove that

`(i) 9 AQ^2 = 9 AC^2 + 4 BC^2`

`(ii) 9 BP^2 = 9 BC^2 + 4 AC^2`

`(iii) 9 (AQ^2 + BP^2 ) = 13 AB^2`

clickto share

#### Solution

You need to to view the solution

Is there an error in this question or solution?

#### Related Questions VIEW ALL [5]

#### Reference Material

Solution for question: In a Right Triangle Abc Right-angled at C, P and Q Are the Points on the Sides Ca and Cb Respectively, Which Divide These Sides in the Ratio 2 : 1. Prove that concept: Pythagoras Theorem. For the course CBSE