# Solution - In the given figure, AD is a median of a triangle ABC and AM ⊥ BC. Prove that: - Pythagoras Theorem

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ConceptPythagoras Theorem

#### Question

In the given figure, AD is a median of a triangle ABC and AM ⊥ BC. Prove that:

1)AC^2 = AD^2 + BC . DM + ((BC)/2)^2

2) AB^2 = AD^2 – BC . DM + ((BC)/2)^2

3) AC^2 + AB^2 = 2 AD^2 + 1/2(BC)^2

#### Solution

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#### Reference Material

Solution for question: In the given figure, AD is a median of a triangle ABC and AM ⊥ BC. Prove that: concept: Pythagoras Theorem. For the course CBSE
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