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Solution - In the given figure, AD is a median of a triangle ABC and AM ⊥ BC. Prove that: - Pythagoras Theorem

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Question

In the given figure, AD is a median of a triangle ABC and AM ⊥ BC. Prove that:

1)`AC^2 = AD^2 + BC . DM + ((BC)/2)^2`

2)` AB^2 = AD^2 – BC . DM + ((BC)/2)^2`

3)` AC^2 + AB^2 = 2 AD^2 + 1/2(BC)^2`

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Solution for question: In the given figure, AD is a median of a triangle ABC and AM ⊥ BC. Prove that: concept: Pythagoras Theorem. For the course CBSE
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