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# For Finding Ab and Bc with the Help of Information Given in the Figure, Complete Following Activity. Ab = Bc .......... - Geometry

ConceptPythagoras Theorem

#### Question

For finding AB and BC with the help of information given in the figure, complete following activity.

AB = BC .......... $\therefore \angle BAC =$ $\therefore AB = BC =$ $\times AC$

$=$ $\times \sqrt{8}$

$=$ $\times 2\sqrt{2}$

=  #### Solution

In ∆ABC,
∠B = 90, AC =$\sqrt{8}$ AB = BC, ∴ ∠A = ∠C = 45

By 45∘ − 45 − 90 theorem,

$AB = BC = \frac{1}{\sqrt{2}} \times AC$
$= \frac{1}{\sqrt{2}} \times \sqrt{8}$
$= \frac{1}{\sqrt{2}} \times 2\sqrt{2}$
$= 2$

Hence, AB = 2 and BC = 2.
Hence, the completed activity is

AB = BC .......... Given

$\therefore \angle BAC = {45}^o$
$\therefore AB = BC = \frac{1}{\sqrt{2}} \times AC$
$= \frac{1}{\sqrt{2}} \times \sqrt{8}$
$= \frac{1}{\sqrt{2}} \times 2\sqrt{2}$
$= 2$

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Solution For Finding Ab and Bc with the Help of Information Given in the Figure, Complete Following Activity. Ab = Bc .......... Concept: Pythagoras Theorem.
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