#### Question

ABC is an isosceles triangle right angled at C. Prove that AB^{2} = 2AC^{2}

#### Solution

Given that ΔABC is an isosceles triangle.

∴ AC = CB

Applying Pythagoras theorem in ΔABC (i.e., right-angled at point C), we obtain

AC^{2} + CB^{2} = AB^{2}

=> AC^{2}+ AC^{2} = AB^{2} (AC = CB)

⇒ 2AC^{2} = AB^{2}

Is there an error in this question or solution?

Solution ABC is an isosceles triangle right angled at C. Prove that AB^2 = 2AC^2 Concept: Pythagoras Theorem.