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Prove that the tangent drawn at the mid-point of an arc of a circle is parallel to the chord joining the end points of the arc.

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#### Solution

Let us draw a circle in which AMB is an arc and M is the mid-point of the arc AMB.

Joined AM and MB.

Also TT' is a tangent at point M on the circle.

**To Prove:** AB || TT'

**Proof:** As M is the mid point of Arc AMB

Arc AM = Arc MB

AM = MB ...[As equal chords cuts equal arcs]

∠ABM = ∠BAM ...[Angles opposite to equal sides are equal] [1]

Now, ∠BMT' = ∠BAM ...[Angle between tangent and the chord equals angle made by the chord in alternate segment] [2]

From [1] and [2]

∠ABM = ∠BMT'

So, AB || TT' ...[Two lines are parallel if the interior alternate angles are equal]

Hence Proved!

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