Advertisement Remove all ads

Prove that Sec2 (90° - θ) + Tan2 (90° - θ) = 1 + 2 Cot2 θ. - Mathematics

Advertisement Remove all ads
Advertisement Remove all ads
Advertisement Remove all ads
Sum

Prove that sec2 (90° - θ) + tan2 (90° - θ) = 1 + 2 cot2 θ.

Advertisement Remove all ads

Solution

LHS = sec2 (90° - θ) + tan2 (90° - θ)

= cosec2θ + cot2θ

= 1 + cot2θ + cot2θ

= 1 + 2cot2θ

= RHS
Hence proved.

Concept: Trigonometric Identities
  Is there an error in this question or solution?

APPEARS IN

ICSE Class 10 Mathematics
Chapter 18 Trigonometry
Exercise | Q 22
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×