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Prove that ΔH=ΔU+ΔnRT. what is the condition under which ΔU=ΔH? - Chemistry

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Prove that ΔH=ΔU+ΔnRT. what is the condition under which ΔU=ΔH?

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Solution

∵ΔH=ΔU+PΔV

 ΔH=ΔU+P(V2-V1)

 ΔH=ΔU+PV2-PV1

 But PV1 = n1RT

 PV2 = n2RT

∴ΔH= ΔU+ n1RT - n2RT

 ΔH= ΔU+RT(n1-n2)

∴ΔH= ΔU+ΔnRT

Condition
i) When reaction is carried out in a closed vessel, so that volume remain constant ΔV=0
ii) When reaction involves only solids or liquids or solutions but no gaseous reactant or product.
iii) When reaction involves gaseous reactants and product but their number of mole are equal.

Concept: Chemical Thermodynamics and Energetic - First Law of Thermodynamics
  Is there an error in this question or solution?

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