Question

Prove that

cosec (67° + θ) − sec (23° − θ) = 0

Answer 1

\[\begin{array}{l} \text{L.H.S}=cosec( {67}^\circ + \theta) - \sec( {23}^\circ-  \theta) \\ \end{array}\]

\[\begin{array}{l}=cosec{ {90}^\circ - ( {23}^\circ-\theta)}-\sec( {23}^\circ - \theta) \\ \end{array}\]

\[\begin{array}{l}=\sec( {23}^\circ -\theta) - \sec( {23}^\circ - \theta) \\ \\ \end{array}\]

\[=0=R.H.S.\]