Advertisement Remove all ads

Prove that: 3 cosec2 60°  - 2 cot2 30°  + sec2 45°  = 0 - Mathematics

Advertisement Remove all ads
Advertisement Remove all ads
Advertisement Remove all ads
Sum

Prove that:

3 cosec2 60°  - 2 cot2 30°  + sec2 45°  = 0

Advertisement Remove all ads

Solution

LHS =3 cosec260° – 2 cot230° + sec245°

=`3(2/sqrt3)^2 – 2(sqrt3)^2 + (sqrt2)^2`

= `3xx4/3-2xx3+2`

= 4 – 6 + 2

= 0

= RHS

Concept: Trigonometric Ratios of Some Special Angles
  Is there an error in this question or solution?

APPEARS IN

Selina Concise Mathematics Class 9 ICSE
Chapter 23 Trigonometrical Ratios of Standard Angles [Including Evaluation of an Expression Involving Trigonometric Ratios]
Exercise 23 (A) | Q 3.6 | Page 291
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×