Sum
Prove that `2 tan^-1 (3/4) = tan^-1(24/7)`
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Solution
`2 tan^-1 (3/4)`
= `tan^-1 (3/4) + tan^-1 (3/4)`
= `tan^-1 ((3/4 + 3/4)/(1 - 3/4 xx 3/4))` .......`[tan^-1"a" + tan^-1"b" = tan^-1(("a" + "b")/(1 - "ab"))]`
= `tan^-1 ((6/4)/(7/16))`
= `tan^-1 (24/7)`
Concept: Inverse Trigonometric Functions
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