Share
Notifications

View all notifications

Prove the Following.Sec2θ + Cosec2θ = Sec2θ × Cosec2θ - Geometry

Login
Create free account


      Forgot password?

Question

Prove the following.
sec2θ + cosec2θ = sec2θ × cosec2θ 

Solution

\[\sec^2 \theta + {cosec}^2 \theta\]
\[ = \frac{1}{\cos^2 \theta} + \frac{1}{\sin^2 \theta}\]
\[ = \frac{\sin^2 \theta + \cos^2 \theta}{\cos^2 \theta \sin^2 \theta}\]
\[ = \frac{1}{\cos^2 \theta \sin^2 \theta}\]
\[ = \frac{1}{\cos^2 \theta} \times \frac{1}{\sin^2 \theta}\]
\[ = \sec^2 \theta  \text{ cosec }^2 \theta\]
  Is there an error in this question or solution?

APPEARS IN

 Balbharati Solution for Balbharati Class 10 Mathematics 2 Geometry (2018 to Current)
Chapter 6: Trigonometry
Problem set 6 | Q: 5.03 | Page no. 138
Solution Prove the Following.Sec2θ + Cosec2θ = Sec2θ × Cosec2θ Concept: Application of Trigonometry.
S
View in app×