A proton and an α -particle are accelerated through the same potential difference. Which one of the two has greater de-Broglie wavelength Justify your answer.
The de Broglie wavelength is related to the accelerating potential as
Now, mass and charge of α particle is greater than that of proton.
∴ λp > λα for the same potential difference.
Concept: de-Broglie Relation
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