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# What Number Must Be Added to Each of the Numbers 6, 15, 20 and 43 to Make Them Proportional? - ICSE Class 10 - Mathematics

#### Questions

What number must be added to each of the numbers 6, 15, 20 and 43 to make them
proportional?

What least number must be added to each of the numbers 6, 15, 20 and 43 to make them proportional?

#### Solution

Let the number added be x.

∴ (6 + x) : (15 + x) :: (20 + x) (43 + x)

=> (6+x)/(15 + x) = (20 + x)/(43 + x)

⇒ (6 + x)(43 + x) (20 + x)(15 + x)

=> 258 + 6x + 43x + x^2 = 300 + 20x + 15x + x^2

=> 49x - 35x = 300 - 258

=> 14x = 42

=> x = 3

Thus, the required number which should be added is 3.

Is there an error in this question or solution?

#### APPEARS IN

Selina Solution for Selina ICSE Concise Mathematics for Class 10 (2018-2019) (2017 to Current)
Chapter 7: Ratio and Proportion (Including Properties and Uses)
Ex.7B | Q: 6

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Solution What Number Must Be Added to Each of the Numbers 6, 15, 20 and 43 to Make Them Proportional? Concept: Proportions.
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