#### Question

What least number must be added to each of the numbers 6, 15, 20 and 43 to make them proportional?

#### Solution

Let the number added be x.

∴ (6 + x) : (15 + x) :: (20 + x) (43 + x)

`=> (6+x)/(15 + x) = (20 + x)/(43 + x)`

⇒ (6 + x)(43 + x) (20 + x)(15 + x)

`=> 258 + 6x + 43x + x^2 = 300 + 20x + 15x + x^2`

`=> 49x - 35x = 300 - 258`

`=> 14x = 42`

`=> x = 3`

Thus, the required number which should be added is 3.

Is there an error in this question or solution?

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What Number Must Be Added to Each of the Numbers 6, 15, 20 and 43 to Make Them Proportional? Concept: Concept of Proportion.

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