#### Questions

What number must be added to each of the numbers 6, 15, 20 and 43 to make them

proportional?

What least number must be added to each of the numbers 6, 15, 20 and 43 to make them proportional?

#### Solution

Let the number added be x.

∴ (6 + x) : (15 + x) :: (20 + x) (43 + x)

`=> (6+x)/(15 + x) = (20 + x)/(43 + x)`

⇒ (6 + x)(43 + x) (20 + x)(15 + x)

`=> 258 + 6x + 43x + x^2 = 300 + 20x + 15x + x^2`

`=> 49x - 35x = 300 - 258`

`=> 14x = 42`

`=> x = 3`

Thus, the required number which should be added is 3.

Is there an error in this question or solution?

Solution What Number Must Be Added to Each of the Numbers 6, 15, 20 and 43 to Make Them Proportional? Concept: Proportions.