ICSE Class 10CISCE
Share
Notifications

View all notifications
Books Shortlist
Your shortlist is empty

What Number Must Be Added to Each of the Numbers 6, 15, 20 and 43 to Make Them Proportional? - ICSE Class 10 - Mathematics

Login
Create free account


      Forgot password?

Questions

What number must be added to each of the numbers 6, 15, 20 and 43 to make them
proportional?

What least number must be added to each of the numbers 6, 15, 20 and 43 to make them proportional?

Solution

Let the number added be x.

∴ (6 + x) : (15 + x) :: (20 + x) (43 + x)

`=> (6+x)/(15 + x) = (20 + x)/(43 + x)`

⇒ (6 + x)(43 + x) (20 + x)(15 + x)

`=> 258 + 6x + 43x + x^2 = 300 + 20x + 15x + x^2`

`=> 49x - 35x = 300 - 258`

`=> 14x = 42`

`=> x = 3`

Thus, the required number which should be added is 3.

  Is there an error in this question or solution?

APPEARS IN

 Selina Solution for Selina ICSE Concise Mathematics for Class 10 (2018-2019) (2017 to Current)
Chapter 7: Ratio and Proportion (Including Properties and Uses)
Ex.7B | Q: 6

Video TutorialsVIEW ALL [1]

Solution What Number Must Be Added to Each of the Numbers 6, 15, 20 and 43 to Make Them Proportional? Concept: Proportions.
S
View in app×