ICSE Class 10CISCE
Share
Notifications

View all notifications
Books Shortlist
Your shortlist is empty

What Least Number Must Be Subtracted from Each of the Numbers 7, 17 and 47 So that the Remainders Are in Continued Proportion? - ICSE Class 10 - Mathematics

Login
Create free account


      Forgot password?

Question

What least number be subtracted from each of the numbers 7, 17 and 47 so that the remainders are in continued proportion?

Solution

Let the number subtracted be x

∴ (7 - x) : (17 - x) :: (17 - x)(47 - x)

`(7 - x)/(47 - x) = (17 - x)^2`

`329 - 47x - 7x + x^2 = 289 - 34x = x^2`

329 - 289 = -34x + 54x

20x = 40

x = 2

Thus the required number which should be subtracted is 2

  Is there an error in this question or solution?

APPEARS IN

 Selina Solution for Selina ICSE Concise Mathematics for Class 10 (2018-2019) (2017 to Current)
Chapter 7: Ratio and Proportion (Including Properties and Uses)
Ex.7B | Q: 8

Video TutorialsVIEW ALL [1]

Solution What Least Number Must Be Subtracted from Each of the Numbers 7, 17 and 47 So that the Remainders Are in Continued Proportion? Concept: Proportions.
S
View in app×