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What Least Number Must Be Added to Each of the Numbers 16, 7, 79 and 43 So that the Resulting Numbers Are in Proportion? - ICSE Class 10 - Mathematics

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Question

What least number must be added to each of the numbers 16, 7, 79 and 43 so that the resulting
numbers are in proportion?

Solution

Let the number added be x.
∴ (16 + x) : (7 + x) :: (79 + x) (43 + x)

`(16 +x)/ (7 + x )`= `(79 +x)/(43 + x)`
(16 + x)(43 + x ) = (79 + x )(7 + x )
688 + 16x + 43x + x2 = 553 + 79x + 7x + x2
688 - 553 = 86x - 59x

135 = 27x
x = 5

Thus, the required number which must be added is 5.

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APPEARS IN

 Selina Solution for Selina ICSE Concise Mathematics for Class 10 (2018-2019) (2017 to Current)
Chapter 7: Ratio and Proportion (Including Properties and Uses)
Ex.7B | Q: 5

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Solution What Least Number Must Be Added to Each of the Numbers 16, 7, 79 and 43 So that the Resulting Numbers Are in Proportion? Concept: Proportions.
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