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Find The Mean Proportional to (X – Y) and (X3 – X2y). - ICSE Class 10 - Mathematics

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Question

Find the mean proportional to (x – y) and (x3 – x2y).

Solution

Let the mean proportional to (x - y) and `(x^3 - x^2y)` be n

`=> (x - y), n, (x^3 - x^2y)` are in continued proportional

`=> (x - y) : n = n : (x^3 - x^2y)`

`=> n^2 = x^2(x - y)(x - y)`

`=> n^2 = x^2(x - y)^2`

`=> n = x(x - y)`

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APPEARS IN

 Selina Solution for Selina ICSE Concise Mathematics for Class 10 (2018-2019) (2017 to Current)
Chapter 7: Ratio and Proportion (Including Properties and Uses)
Ex.7D | Q: 9.3

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Solution Find The Mean Proportional to (X – Y) and (X3 – X2y). Concept: Proportions.
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