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Prove that is sqrt3 irrational number. - CBSE Class 10 - Mathematics

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Prove that is `sqrt3` irrational number.


Let us assume, to contrary, that  is rational. That is, we can find integers a and b (≠0) such that `sqrt2=a/b`

Suppose a and b not having a common factor other than 1, then we can divide by the common factor, and assume that a and b are coprime.

So, b`sqrt3`= a

Squaring on both sides, and rearranging, we get 3b2 = a2.

Therefore, a2 is divisible by 3, and by Theorem, it follows that a is also divisible by 3.

So, we can write a = 3c for some integer c.

Substituting for a, we get 3b2 = 9c2, that is, b2 = 3c2.

This means that b2 is divisible by 3, and so b is also divisible by 3 (using Theorem with p = 3).

Therefore, a and b have at least 3 as a common factor.

But this contradicts the fact that a and b are coprime.

This contradicts the fact that a and b are coprime.

This contradiction has arisen because of our incorrect assumption that `sqrt3` is rational.

So, we conclude that `sqrt3` is irrational.

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Solution Prove that is sqrt3 irrational number. Concept: Proofs of Irrationality.
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