#### Question

The short and long hands of a clock are 4 cm and 6 cm long respectively. Find the sum of distances travelled by their tips in 2 days. (Take π = 22/7)

#### Solution

In 2 days, the short hand will complete 4 rounds.

∴ Distance moved by its tip = 4 (Circumference of a circle of radius 4 cm)

`=4\times ( 2\times \frac{22}{7}\times 4)=\frac{704}{7}\text{ cm}`

In 2 days, the long hand will complete 48 rounds.

∴ Distance moved by its tip

= 48 (Circumference of a circle of radius 6 cm)

`=48\times ( 2\times \frac{22}{7}\times 4 )=\frac{12672}{7}\text{ cm}`

Hence,

Sum of the distance moved by the tips of two hands of the clock

`=( \frac{704}{7}+\frac{12672}{7})=1910.57`

Is there an error in this question or solution?

Solution The short and long hands of a clock are 4 cm and 6 cm long respectively. Find the sum of distances travelled by their tips in 2 days. (Take π = 22/7) Concept: Problems Based on Areas and Perimeter Or Circumference of Circle, Sector and Segment of a Circle.