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A bag contains twenty Rs 5 coins, fifty Rs 2 coins and thirty Re 1 coins. If it is equally likely that one of the coins will fall down when the bag is turned upside down, what is the probability that the coin:  will neither be a Rs 5 coin nor be a Re 1 coin? - ICSE Class 10 - Mathematics

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Question

A bag contains twenty Rs 5 coins, fifty Rs 2 coins and thirty Re 1 coins. If it is equally likely that one of the coins will fall down when the bag is turned upside down, what is the probability that the coin: 

will neither be a Rs 5 coin nor be a Re 1 coin?

Solution

Total number of coins =20+50+30=100 

Total possible outcomes=100=n(s) 

Number of favorable outcomes for niether Re1 nor Rs5 coins= Number of favourable outcomes for  Rs2 coins=50= n(E) 

Probability (neither Re 1 nor Rs 5 coin)=`(n(E))/(n(s))=50/100=1/2`

  Is there an error in this question or solution?
Solution A bag contains twenty Rs 5 coins, fifty Rs 2 coins and thirty Re 1 coins. If it is equally likely that one of the coins will fall down when the bag is turned upside down, what is the probability that the coin:  will neither be a Rs 5 coin nor be a Re 1 coin? Concept: Probability - A Theoretical Approach.
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