#### Question

A bag contains twenty Rs 5 coins, fifty Rs 2 coins and thirty Re 1 coins. If it is equally likely that one of the coins will fall down when the bag is turned upside down, what is the probability that the coin:

will be a Re 1 coin?

#### Solution

Total number of coins = 20+50+30=100

Total possible outcomes=100=n(S)

Number of favorable outcomes for Re 1 coins=30=n(s)

Probability (Re 1 coin)=`( n(E))/(n(S))=30/100=3/10 `

Is there an error in this question or solution?

Solution A Bag Contains Twenty Rs 5 Coins, Fifty Rs 2 Coins and Thirty Re 1 Coins. If It is Equally Likely that One of the Coins Will Fall Down When the Bag is Turned Upside Down, What is the Probability that the Coin: Will Be a Re 1 Coin? Concept: Probability - A Theoretical Approach.