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A Bag Contains Twenty Rs 5 Coins, Fifty Rs 2 Coins and Thirty Re 1 Coins. If It is Equally Likely that One of the Coins Will Fall Down When the Bag is Turned Upside Down, What is the Probability that the Coin: Will Be a Re 1 Coin? - Mathematics

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Question

A bag contains twenty Rs 5 coins, fifty Rs 2 coins and thirty Re 1 coins. If it is equally likely that one of the coins will fall down when the bag is turned upside down, what is the probability that the coin: 

 will be a Re 1 coin? 

Solution

Total number of coins = 20+50+30=100 

Total possible outcomes=100=n(S) 

Number of favorable outcomes for Re 1 coins=30=n(s) 

Probability (Re 1 coin)=`( n(E))/(n(S))=30/100=3/10 ` 

  Is there an error in this question or solution?
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APPEARS IN

 Selina Solution for Concise Mathematics for Class 10 ICSE (2020 (Latest))
Chapter 25: Probability
Exercise 25(C) | Q: 17.1 | Page no. 395
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Solution A Bag Contains Twenty Rs 5 Coins, Fifty Rs 2 Coins and Thirty Re 1 Coins. If It is Equally Likely that One of the Coins Will Fall Down When the Bag is Turned Upside Down, What is the Probability that the Coin: Will Be a Re 1 Coin? Concept: Probability - A Theoretical Approach.
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