#### Question

A and B are events such that P(A) = 0.42, P(B) = 0.48 and P(A and B) = 0.16. Determine P(not A)

#### Solution

It is given that P(A) = 0.42, P(B) = 0.48, P(A and B) = 0.16

P(not A) = 1 – P(A) = 1 – 0.42 = 0.58

Is there an error in this question or solution?

Solution A and B Are Events Such that P(A) = 0.42, P(B) = 0.48 and P(A and B) = 0.16. Determine P(Not A) Concept: Probability - Probability of 'Not', 'And' and 'Or' Events.