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# An Integer is Chosen at Random Between 1 and 100. Find the Probability that It is Divisible by 8 and Not Divisible by 8. - CBSE Class 10 - Mathematics

ConceptProbability Examples and Solutions

#### Question

An integer is chosen at random between 1 and 100. Find the probability that it is

1) divisible by 8.

2) not divisible by 8.

#### Solution

S = {2, 3 ..., 99}

n(S) = 98

1) A: Getting an integer divisible by 8.

A = {8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96}

n(A) = 12

P(A) = (n(A))/(n(s)) = 12/98  = 0.1224

2) B: Getting an integer not divisible by 8

P(B) = 1 -">- Probability of getting integer divisible by 8

P(B) = 1 -">- P(A) = 1 - 0.1224 = 0.8756

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Solution An Integer is Chosen at Random Between 1 and 100. Find the Probability that It is Divisible by 8 and Not Divisible by 8. Concept: Probability Examples and Solutions.
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