HSC Arts 12th Board ExamMaharashtra State Board
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# Probability distribution of X is given by - HSC Arts 12th Board Exam - Mathematics and Statistics

ConceptRandom Variables and Its Probability Distributions

#### Question

Probability distribution of X is given by

 X = x 1 2 3 4 P(X = x) 0.1 0.3 0.4 0.2

Find P(X ≥ 2) and obtain cumulative distribution function of X

#### Solution

By definition cummulative distribution function at x is

P(x ≥ 2) = 0.3 + 0.4 + 0.2 = 0.9
f (x_i) = P_1 + P_2 + P_3 + ……. + P_i where, i = 1, …, x

Thus f(x_1)=P_1=0.1

f(x_2)=P_1=0.1

f(x_2)=P_1+P_2=0.1+0.3=0.4

f(x_3)=P_1+P_2+P_3=0.1+0.3+0.4=0.8

f(x_4)=P_1+P_2+P_3+P_4=0.1+0.3+0.4+0.2=1

therefore f(x_4)=sum_(i=1)^4P_i=1

 X = x 1 2 3 4 P(X = x) 0.1 0.4 0.8 1
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#### APPEARS IN

2016-2017 (July) (with solutions)
Question 6.1.3 | 3.00 marks

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Solution Probability distribution of X is given by Concept: Random Variables and Its Probability Distributions.
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