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# Solution for The Probability that a Person Who Undergoes Kidney Operation Will Recover is 0.5. Find the Probability that of the Six Patients Who Undergo Similar Operations - HSC Science (Computer Science) 12th Board Exam - Mathematics and Statistics

ConceptProbability Distribution of a Discrete Random Variable

#### Question

The probability that a person who undergoes kidney operation will recover is 0.5. Find the probability that of the six patients who undergo similar operations,

(a) None will recover

(b) Half of them will recover.

#### Solution 1

Probability of recovery=P(R)= 0.5
Probability of non-recovery = P(barR)=1-0.5=0.5

(a) If there are six patients, the probability that none recovers

=^6C_0xx[P(R)]^0xx[P(barR)]^6=(0.5)^6=1/64

(b) Of the six patients, the probability that half will recover

=^6C_3xx[P(R)]^3xx[P(barR)]^3=(6!)/(3!3!)xx0.5^3xx0.5^3=20xx1/64=5/16

#### Solution 2

Let X be the number of patients who recovered out of 6.

P(patient recovers) = p = 0.5

∴ q = 1 − p = 1 − 0.5 = 0.5

Given, n = 6

∴ X ~ B(6, 0.5)

The p.m.f. of X is given by

P(X = x) = p(x) = ""^6C_x(0.5)x(0.5)6−x, x = 0, 1, 2, ...., 6

a)P(none will recover) = P (X = 0)

= ""^6C_0(0.5)0(0.5)6

= (1) (1) (0.5)6

= 0.015625

(b) P(half of the patients will recover) = P (X = 3)

= ""^6C_3(0.5)3(0.5)3

= 20 (0.5)6

= 20 × 0.015625

= 0.3125

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Solution for question: The Probability that a Person Who Undergoes Kidney Operation Will Recover is 0.5. Find the Probability that of the Six Patients Who Undergo Similar Operations concept: Probability Distribution of a Discrete Random Variable. For the courses HSC Science (Computer Science), HSC Science (Electronics), HSC Science (General) , HSC Arts, HSC Commerce (Marketing and Salesmanship), HSC Commerce
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