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# Solution - In Problem 10.9, If 15.0 Cm of Water and Spirit Each Are Further Poured into the Respective Arms of the Tube, What is the Difference in the Levels of Mercury in the Two Arms? (Specific Gravity of Mercury = 13.6) - Pressure - Concept of Pressure

ConceptPressure Concept of Pressure

#### Question

In problem 10.9, if 15.0 cm of water and spirit each are further poured into the respective arms of the tube, what is the difference in the levels of mercury in the two arms? (Specific gravity of mercury = 13.6)

#### Solution

Height of the water column, h1 = 10 + 15 = 25 cm

Height of the spirit column, h2 = 12.5 + 15 = 27.5 cm

Density of water, ρ1 = 1 g cm–3

Density of spirit, ρ2 = 0.8 g cm–3

Density of mercury = 13.6 g cm–3

Let h be the difference between the levels of mercury in the two arms.

The pressure exerted by height h, of the mercury column:

g

h × 13.6g … (i)

Difference between the pressures exerted by water and spirit:

=h_1rho_1g - h_1rho_1g

= g(25 × 1 – 27.5 × 0.8)

= 3g … (ii)

Equating equations (i) and (ii), we get:

13.6 hg = 3g

h = 0.220588 ≈ 0.221 cm

Hence, the difference between the levels of mercury in the two arms is 0.221 cm.

Is there an error in this question or solution?

#### APPEARS IN

NCERT Physics Textbook for Class 11 Part 2
Chapter 10: Mechanical Properties of Fluids
Q: 10 | Page no. 269

#### Reference Material

Solution for question: In Problem 10.9, If 15.0 Cm of Water and Spirit Each Are Further Poured into the Respective Arms of the Tube, What is the Difference in the Levels of Mercury in the Two Arms? (Specific Gravity of Mercury = 13.6) concept: Pressure - Concept of Pressure. For the courses CBSE (Arts), CBSE (Commerce), CBSE (Science)
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