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Sum
Prepare truth tables for the following statement pattern.
(p ∧ r) → (p ∨ ~ q)
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Solution
(p ∧ r) → (p ∨ ~ q)
| p | q | r | ~q | p ∧ r | p∨~q | (p ∧ r) → (p ∨ ~ q) |
| T | T | T | F | T | T | T |
| T | T | F | F | F | T | T |
| T | F | T | T | T | T | T |
| T | F | F | T | F | T | T |
| F | T | T | F | F | F | T |
| F | T | F | F | F | F | T |
| F | F | T | T | F | T | T |
| F | F | F | T | F | T | T |
Is there an error in this question or solution?
